To model the number of fruit flies using the equation \( f(t) = 8 \cdot (2)^t \), we can calculate the number of fruit flies for \( t = 0 \) to \( t = 6 \):
-
At t = 0:
\( f(0) = 8 \cdot (2)^0 = 8 \cdot 1 = 8 \) -
At t = 1:
\( f(1) = 8 \cdot (2)^1 = 8 \cdot 2 = 16 \) -
At t = 2:
\( f(2) = 8 \cdot (2)^2 = 8 \cdot 4 = 32 \) -
At t = 3:
\( f(3) = 8 \cdot (2)^3 = 8 \cdot 8 = 64 \) -
At t = 4:
\( f(4) = 8 \cdot (2)^4 = 8 \cdot 16 = 128 \) -
At t = 5:
\( f(5) = 8 \cdot (2)^5 = 8 \cdot 32 = 256 \) -
At t = 6:
\( f(6) = 8 \cdot (2)^6 = 8 \cdot 64 = 512 \)
Now, we can summarize the values:
- Day 0: 8
- Day 1: 16
- Day 2: 32
- Day 3: 64
- Day 4: 128
- Day 5: 256
- Day 6: 512
With this exponential growth (doubling each day), the graph will show a steep upward curve starting at 8 and rapidly increasing to 512 over the 6 days.
Since I don't have the actual graphs to look at, you should look for a graph that:
- Starts at around 8 on Day 0
- Doubles each day and reaches approximately 512 by Day 6
- Exhibits an exponential growth pattern, curving upwards steeply as t increases.
Choose the graph that matches this description!
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