by plotting the graph of parabola y=2+3x-2x^2 which 3 option are true
1) the graph is the same as that of y=6+9x-6x^2
2)the parabola has a minimum point
3)the gradient of the parabola at x=2 is 0
4)the graphy=2+3x-2x^2crosses the x-axis at the same point as the graph y=6+9x-6x^2
5)the vertex of the parabola is at(1,5)
6)the equation of the axis of symmetery is y=-1
7)the gradient of the parabola is positive when x=0
8)the intercept on the y axis is at y=2
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Have you plotted this on your calculator?
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