By how many decibels does the sound intensity from a point source decrease if you increase the distance to it by a factor 6?

Answer 1

Surface area is proportional to distance^2

so if you increase distance by 6, then sound goes down by a factor of 1/36.

db= 10log(1/6)

so db goes down by a factor of 7.78

so if the original were 40 db, the new is 32.22 db