Asked by Riley
By graphing a system of constraints, find the values of x and y that maximize the objective function.
x+y less than it equal to 8
2x + y is less than it equal to 10
x is great her than it equal to 0
y is great her than it equal to 0
x+y less than it equal to 8
2x + y is less than it equal to 10
x is great her than it equal to 0
y is great her than it equal to 0
Answers
Answered by
Reiny
x+y less than it equal to 8 ----> x+y is less than or equal to 8 ---> x + y ≤ 8
2x + y is less than it equal to 10 ---> 2x+y is less than or equal to 10 ---> 2x + y ≤ 10
x is great her than it equal to 0 ----> x is greater than or equal to 0 ---> x ≥ 0
y is great her than it equal to 0 ---> y is greater than or equal to 0 ---> y ≥ 0
??? great her ?????
Did you sketch the two lines?
The last two condition simply tell you look only in the first quadrant.
intersection of the two lines:
x+y = 8
2x + y = 10
subtract them:
x = 2, and then y = 6
Now it would be helpful if I knew what the objective function is.
2x + y is less than it equal to 10 ---> 2x+y is less than or equal to 10 ---> 2x + y ≤ 10
x is great her than it equal to 0 ----> x is greater than or equal to 0 ---> x ≥ 0
y is great her than it equal to 0 ---> y is greater than or equal to 0 ---> y ≥ 0
??? great her ?????
Did you sketch the two lines?
The last two condition simply tell you look only in the first quadrant.
intersection of the two lines:
x+y = 8
2x + y = 10
subtract them:
x = 2, and then y = 6
Now it would be helpful if I knew what the objective function is.
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