By considering a wire of radius 'r', lenght 'l' and resistivity 'e' through which a current I flows, show that
a) the rate of production of heat by it is I^2*P*l / pi*r^2
b) the rate of loss of heat from its surface is 2pi*r*t*h , where 'h' is the heat lost per unit area of surface per second.
2 answers