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Bromine will react with limonene according to this reaction (there's a picture, but I can't get that on here. So I'll do my best to write it out).

136.23 g/mol + Br2 ------> 296.04 g/mol

Suppose 627 mg of limonene was reacted with 3.7 mL of a 7.7% (v/v) solution of Br2 in dichloromethane (a solvent), and after purification, 921 mg of the brominated producted was isolated. What was the percent yield?

% yield: ________%

Please help me! I don't even know where to start this problem.

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