Let's break down your request step by step.
-
Breaking up 31 into base ten blocks:
- 31 can be represented as 3 tens (which equals 30) and 1 one.
- So, \( 31 = 3 \times 10 + 1 \times 1 \).
-
Breaking up 11 into base ten blocks:
- 11 can be represented as 1 ten and 1 one.
- So, \( 11 = 1 \times 10 + 1 \times 1 \).
-
Creating an array using base ten blocks:
- You mentioned that we're going to make an array that has "? columns" and "11 ?".
- From the breakdowns:
- We already established that 31 can be arranged in columns of tens and ones. To find out how to represent 11 in a similar format, we could see how they relate.
Arranging in columns:
- If we're considering the number 11, we can interpret it as having:
- 1 column of tens (representing 1 ten).
- 1 column of ones (representing 1 one).
Putting it together, if we're making an array using base ten blocks for 31 and 11, it seems like you would be interested in:
- Array representation for 31: 3 columns (for the 3 tens) and 1 column (for the 1 one).
- Array representation for 11: 1 column (for the 1 ten) and 1 column (for the 1 one).
So, the final interpretation would be:
- You can create an array with 1 column of tens and 1 column of ones to represent 11. If you're directly constructing, you could be looking for an array with 3 columns for tens and 1 column for ones to give a visual representation of 31.
If you're asking how many columns the total array would have:
- If you're looking at the maximum representation of either, you can use 3 columns for tens (from 31) and if you align the 1 column of tens from 11, the total makes 4 columns (3 for the tens and possibly 1 for the ones for 31).
In summary:
- The array has 3 columns for tens and 1 column for ones, for a total of 4 columns visually if you track the sum resemblance.