Brandon and Albert had $240 altogether. Albert gave 2/5 of his money money to Brandon. After that, Brandon gave 3/5 of his money to Albert. In the end, Brandon had 1/4 of the total sum of money. How much did Brandon have at first?

Answer 1

Let B be the amount Brandon had at first.
Then, Albert had 240 - B at first and 2/5 * (240 - B) after giving some money to Brandon.
After Albert gave money to Brandon, he had (240 - B) - 2/5 * (240 - B) = 3/5 * (240 - B) left.
After Brandon gave some money to Albert, he had (1 - 3/5) * (240 - B) = 1/4 * (240 - B).
Thus, (1/4) * (240 - B) = B.
240 - B = 4B.
5B = 240.
B = <<48=48>>48. Answer: \boxed{48}.