Y = (1/9)(X^2) = X^2/9.
a. Y = X^2/9 = 25 ft.
X^2/9 = 25,
Multiply both sides by 9:
X^2 = 225,
X = 15 Miles/hr.
Braking distance The braking distance y in feetthat it takes for a car to stop on wet ,level pavement can be estimated by y = 1/9 x^2, where the x is the speed of the car in miles per hour Find the speed associated with with each braking distance.
(a.) 25 feet (b.) 361 (c.) 784
2 answers
post it.
1 answer