To find which class has the greater ratio of green-eyed students to total students, we need to calculate the ratio for each class.
For Brad's class:
- Number of students with green eyes = 3
- Total number of students = 25
The ratio of green-eyed students in Brad's class is:
\[ \text{Ratio for Brad's class} = \frac{3}{25} \]
For Lena's class:
- Number of students with green eyes = 2
- Total number of students = 20
The ratio of green-eyed students in Lena's class is:
\[ \text{Ratio for Lena's class} = \frac{2}{20} \]
To compare these two ratios, we can simplify Lena's ratio:
\[ \frac{2}{20} = \frac{1}{10} \]
Next, we need to compare \(\frac{3}{25}\) and \(\frac{1}{10}\). To do this, we can convert both fractions to have a common denominator. The least common multiple of 25 and 10 is 50.
Now, we convert \(\frac{3}{25}\):
\[ \frac{3}{25} = \frac{3 \times 2}{25 \times 2} = \frac{6}{50} \]
Now, we convert \(\frac{1}{10}\):
\[ \frac{1}{10} = \frac{1 \times 5}{10 \times 5} = \frac{5}{50} \]
Now we can compare these two fractions:
- Brad's class: \(\frac{6}{50}\)
- Lena's class: \(\frac{5}{50}\)
Since \(\frac{6}{50} > \frac{5}{50}\), Brad's class has a greater ratio of green-eyed students to total students.
Thus, Brad's class has the greater ratio of green-eyed students to total students.
2 answers