Assign oxidation numbers and you will know.
Br2(aq) + 2 KI(aq) ==> 2 KBr(aq) + I2(s)
Br2 is zero for each on the left to 2- on the right.
2I is 2- on the left to zero on the right.
Oxidation is the loss of electrons.
Reduction is the gain of electrons.
Br2(aq) + 2 KI(aq) ==> 2 KBr(aq) + I2(s)
What is oxidized and what is reduced in this reaction?
3 answers
Bromine oxidiation number decreases (gains electron), Iodine loses an electron (loxidation number increases) https://qph.fs.quoracdn.net/main-qimg-c4dec6c49e9a1e0f1733c33ed5ec766c
oxidation-reduction 2KBr+I2
3 answers