Using Boyle's Law:
P1V1 = P2V2
Where P1 is the initial pressure (158 kPa), V1 is the initial volume (5 L), P2 is the final pressure (unknown), and V2 is the final volume (2 L).
Plugging in the numbers:
158 kPa * 5 L = P2 * 2 L
790 kPa = P2
Therefore, the pressure when the volume is 2 L is 790 kPa.
Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is
5 L
, the pressure is
158 kPa
(kilopascals). What is the pressure when the volume is
2 L
?
1 answer