Let's assume the width of the rectangle that Boye cuts out is "w" inches.
The perimeter of a rectangle is given by the formula P = 2l + 2w, where "l" is the length and "w" is the width.
Given that the length of the rectangle is 8 inches and the perimeter is 26 inches, we can set up the equation:
26 = 2(8) + 2w
Simplifying this equation gives us:
26 = 16 + 2w
Subtracting 16 from both sides, we have:
10 = 2w
Dividing both sides by 2, we get:
5 = w
So the width of the rectangle Boye cuts out is 5 inches.
Now let's find the dimensions of the new rectangle. The length remains the same at 8 inches, and the width is twice as wide as the original rectangle, so it is 2 * 5 = 10 inches.
The perimeter of the new rectangle is given by the formula P = 2l + 2w:
P = 2(8) + 2(10) = 16 + 20 = 36
Therefore, the perimeter of the new rectangle is 36 inches.
Boye cuts out a rectangle that has a perimeter of 26 inches and a length of 8 inches. He cuts out another rectangle that is the same length and twice as wide.
What is the perimeter of the new rectangle?
@
inch(es)
1 answer