In order to estimate the difference in the expected number of white and red balls in bowl B, we'll need to calculate the probability of selecting a white and red ball from each bowl.
Let:
- Let x be the number of white balls in bowl B
- Let y be the number of red balls in bowl B
Since there are a total of 500 balls in bowl B, we have the equation x + y = 500.
Given that Clark repeatedly selected a ball from both bowls, we can assume that the probability of selecting a white ball from bowl B is equal to the probability of selecting a white ball from bowl A.
Therefore, the expected number of white balls in bowl B is equal to the expected number of white balls in bowl A.
Let p be the probability of selecting a white ball from either bowl.
So, the expected number of white balls in bowl B is p * 500 = 500p.
Similarly, the expected number of red balls in bowl B is (1 - p) * 500 = 500(1 - p).
The estimated difference in the expected number of white and red balls in bowl B is:
(500p) - (500(1 - p)) = 1000p - 500
Therefore, the estimated difference in the expected number of white and red balls in bowl B is 1000p - 500.
Bowls ANB contain a number of white and red balls.Clark repeatedly selected a ball from both bowls and recorded the results in a table.If there are five hundred balls in bowl b what is the estimated difference in the expected number of white and red balls in bowl b
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