The expected proportion of white balls in Bowl B is simply the average of the proportion of white balls selected from Bowl B in each trial:
(60/100 + 45/100)/2 = 0.525
Similarly, the expected proportion of red balls in Bowl B is:
(40/100 + 55/100)/2 = 0.475
If there are 500 balls in Bowl B, we can estimate the number of white balls as:
0.525 x 500 = 262.5
And the number of red balls as:
0.475 x 500 = 237.5
The estimated difference in the expected number of white and red balls in Bowl B is:
262.5 - 237.5 = 25
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 25.
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
Bowl A : 45, 55
Bowl B : 60, 40
Number of white balls selected : 45, 60
Number of red balls selected : 55, 40
1 answer