In Bowl A, the probability of selecting a white ball is 45/100 = 0.45 and the probability of selecting a red ball is 55/100 = 0.55.
In Bowl B, the probability of selecting a white ball is 60/100 = 0.6 and the probability of selecting a red ball is 40/100 = 0.4.
Since Clark repeatedly selected a ball from both bowls, the expected number of white balls selected from Bowl B can be calculated as:
Expected number of white balls = 0.6 * Number of balls in Bowl B = 0.6 * 500 = 300 white balls
Similarly, the expected number of red balls selected from Bowl B can be calculated as:
Expected number of red balls = 0.4 * Number of balls in Bowl B = 0.4 * 500 = 200 red balls
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is:
300 white balls - 200 red balls = 100 balls
The estimated difference in the expected number of white and red balls in Bowl B is 100 balls.
Bowl a 45 white balls 55 red balls
Bowl b 60 white balls 40 red balls
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
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