Bowl #1 contains 4 grape candies, 5 lemon candies, 6 cherry candies and 5 raspberry candies.

Bowl #2 contains 8 grape candies, 5 lemon candies, 4 cherry candies and 3 raspberry candies.

(c) What is the probability that the two selected candies are the same flavour?

(d) What is the probability that the two selected candies are different colours?

(e) What is the probability that the first selected candy is lemon or that the second selected candy is cherry?

2 answers

Am I to assume one candy is selected at random from each bowl?

If so, then c) Pr=4/20*8/20
d) pr=1-pr(same)=1=4/20*8/20-5/20*5/20 - 6/20*4/20-5/20*3/20

e. pr=5/20*4/20
yes but how are you getting e?

P(Lemon)+P(Cherry)-P(Lemon n Cherry)

is a formula that was given earlier today just don't quite understand.