Both of these tables represent linear graphs:%0D%0A%0D%0A%0D%0A%0D%0ADoes the line through the first set of points intersect with the line through the second set of points?%0D%0A%0D%0A(1 point)

Answer 1

To determine if the line through the first set of points intersects with the line through the second set of points, we would need to see the actual tables or the coordinates of the points in each set. Without that information, it is not possible to determine if the lines intersect.

Answer 2

First table X (-3, -2, -1, 0, 1, 2, 3, 4) Y (8, 10, 12, 14, 16, 18, 20, 22)
Second table X(-3, -2, -1, 0 , 1, 2, 3, 4) Y (-2, 0, 2, 4, 6, 8, 10, 12)

Answer 3

To determine if the line through the first set of points intersects with the line through the second set of points, we can calculate the slopes and y-intercepts for each line.

For the first set of points:
x1 = -3, y1 = 8
x2 = 4, y2 = 22

Slope1 = (y2 - y1) / (x2 - x1) = (22 - 8) / (4 - (-3)) = 14 / 7 = 2

Using the point-slope form, we can choose any point from the first set of points, let's use (x1, y1) = (-3, 8):

y - y1 = Slope1 * (x - x1)
y - 8 = 2 * (x - (-3))
y - 8 = 2x + 6
y = 2x + 14

So, the equation for the line through the first set of points is y = 2x + 14.

For the second set of points:
x3 = -3, y3 = -2
x4 = 4, y4 = 12

Slope2 = (y4 - y3) / (x4 - x3) = (12 - (-2)) / (4 - (-3)) = 14 / 7 = 2

Using the point-slope form, we can choose any point from the second set of points, let's use (x3, y3) = (-3, -2):

y - y3 = Slope2 * (x - x3)
y - (-2) = 2 * (x - (-3))
y + 2 = 2x + 6
y = 2x + 4

So, the equation for the line through the second set of points is y = 2x + 4.

Comparing the slopes and y-intercepts of the two lines, we can see that both lines have the same slope (2). However, their y-intercepts are different (y-intercept1 = 14 and y-intercept2 = 4). Since the slopes are equal but the y-intercepts are different, the lines are parallel and do not intersect.