To find the surface area of a right rectangular prism, you can use the formula: 2lw + 2lh + 2wh, where l = length, w = width, and h = height.
Given:
Length = 4.5 cm
Width = 3.5 cm
Height = 2.5 cm
Surface Area = 2(4.5*3.5) + 2(4.5*2.5) + 2(3.5*2.5)
Surface Area = 2(15.75) + 2(11.25) + 2(8.75)
Surface Area = 31.5 + 22.5 + 17.5
Surface Area = 71.5 cm^2
Therefore, the surface area of the shape with the given measurements is 71.5 cm^2.
@bot Use the formula for the surface area of a right rectangular prism to find the surface area of a shape with the following measurements: Length = 4.5 cm, width = 3.5 cm, and height = 2.5 cm.
35.75 cm^2
63 cm^2
71.5 cm^2
10.5 cm^2
9 answers
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Use the formula for the surface area of a right rectangular prism to find the surface area of a shape with the following measurements: Length = 4.5 cm, width = 3.5 cm, and height = 2.5 cm.
answers:
35.75 cm^2
63 cm^2
71.5 cm^2
10.5 cm^2
Use the formula for the surface area of a right rectangular prism to find the surface area of a shape with the following measurements: Length = 4.5 cm, width = 3.5 cm, and height = 2.5 cm.
answers:
35.75 cm^2
63 cm^2
71.5 cm^2
10.5 cm^2
To find the surface area of a right rectangular prism, you can use the formula: 2lw + 2lh + 2wh, where l = length, w = width, and h = height.
Given:
Length = 4.5 cm
Width = 3.5 cm
Height = 2.5 cm
Surface Area = 2(4.5*3.5) + 2(4.5*2.5) + 2(3.5*2.5)
Surface Area = 2(15.75) + 2(11.25) + 2(8.75)
Surface Area = 31.5 + 22.5 + 17.5
Surface Area = 71.5 cm^2
Therefore, the surface area of the shape with the given measurements is 71.5 cm^2. The correct answer is 71.5 cm^2.
Given:
Length = 4.5 cm
Width = 3.5 cm
Height = 2.5 cm
Surface Area = 2(4.5*3.5) + 2(4.5*2.5) + 2(3.5*2.5)
Surface Area = 2(15.75) + 2(11.25) + 2(8.75)
Surface Area = 31.5 + 22.5 + 17.5
Surface Area = 71.5 cm^2
Therefore, the surface area of the shape with the given measurements is 71.5 cm^2. The correct answer is 71.5 cm^2.
Use the formula to determine the surface area of a right rectangular prism where each edge length measures 12.75 cm.(1 point)
Responses
459 cm^2
5,852.25 cm^2
76.5 cm^2
975.38 cm^2
Responses
459 cm^2
5,852.25 cm^2
76.5 cm^2
975.38 cm^2
Given:
Length = Width = Height = 12.75 cm
To find the surface area of a right rectangular prism with each edge length measuring 12.75 cm, we use the formula: 2lw + 2lh + 2wh.
Surface Area = 2(12.75*12.75) + 2(12.75*12.75) + 2(12.75*12.75)
Surface Area = 2(162.5625) + 2(162.5625) + 2(162.5625)
Surface Area = 325.125 + 325.125 + 325.125
Surface Area = 975.375
Therefore, the surface area of the right rectangular prism with each edge length measuring 12.75 cm is 975.38 cm^2. The correct answer is 975.38 cm^2.
Length = Width = Height = 12.75 cm
To find the surface area of a right rectangular prism with each edge length measuring 12.75 cm, we use the formula: 2lw + 2lh + 2wh.
Surface Area = 2(12.75*12.75) + 2(12.75*12.75) + 2(12.75*12.75)
Surface Area = 2(162.5625) + 2(162.5625) + 2(162.5625)
Surface Area = 325.125 + 325.125 + 325.125
Surface Area = 975.375
Therefore, the surface area of the right rectangular prism with each edge length measuring 12.75 cm is 975.38 cm^2. The correct answer is 975.38 cm^2.
Find the surface area of a textbook that is 2 in. × 14 in. × 9 in.(1 point)
Responses
50 in^2
172 in^2
252 in^2
344 in^2
Responses
50 in^2
172 in^2
252 in^2
344 in^2
Given:
Length = 14 in
Width = 9 in
Height = 2 in
To find the surface area of the textbook, we use the formula: 2lw + 2lh + 2wh.
Surface Area = 2(14*9) + 2(14*2) + 2(9*2)
Surface Area = 2(126) + 2(28) + 2(18)
Surface Area = 252 + 56 + 36
Surface Area = 344 in^2
Therefore, the surface area of the textbook is 344 in^2. The correct answer is 344 in^2.
Length = 14 in
Width = 9 in
Height = 2 in
To find the surface area of the textbook, we use the formula: 2lw + 2lh + 2wh.
Surface Area = 2(14*9) + 2(14*2) + 2(9*2)
Surface Area = 2(126) + 2(28) + 2(18)
Surface Area = 252 + 56 + 36
Surface Area = 344 in^2
Therefore, the surface area of the textbook is 344 in^2. The correct answer is 344 in^2.
Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)
Responses
Book A will require less wrapping paper because its surface area is 1.5 in^2
1.5 in^2 less than the surface area of Book B.
Book B will require less wrapping paper because its surface area is 1.5 in.2
1.5 in^2 less than the surface area of Book A.
Book A will require less wrapping paper because its surface area is 32.75 in^2
32.75 in^2 less than the surface area of Book B.
Book B will require less wrapping paper because its surface area is 0.5 in^2
0.5 in^2 less than the surface area of Book A.
Responses
Book A will require less wrapping paper because its surface area is 1.5 in^2
1.5 in^2 less than the surface area of Book B.
Book B will require less wrapping paper because its surface area is 1.5 in.2
1.5 in^2 less than the surface area of Book A.
Book A will require less wrapping paper because its surface area is 32.75 in^2
32.75 in^2 less than the surface area of Book B.
Book B will require less wrapping paper because its surface area is 0.5 in^2
0.5 in^2 less than the surface area of Book A.
To compare which book will require less wrapping paper, we need to calculate the surface area of each book using the formula: 2lw + 2lh + 2wh.
For Book A:
Length = 6.5 inches
Width = 1 inch
Height = 8.5 inches
Surface Area of Book A = 2(6.5*1) + 2(6.5*8.5) + 2(1*8.5)
Surface Area of Book A = 13 + 110.5 + 17
Surface Area of Book A = 140.5 in^2
For Book B:
Length = 5.5 inches
Width = 2 inches
Height = 8 inches
Surface Area of Book B = 2(5.5*2) + 2(5.5*8) + 2(2*8)
Surface Area of Book B = 22 + 88 + 32
Surface Area of Book B = 142 in^2
Therefore, Book A has a surface area of 140.5 in^2, and Book B has a surface area of 142 in^2. Book A will require less wrapping paper as its surface area is less than that of Book B. The provided responses do not seem accurate based on the calculations above.
For Book A:
Length = 6.5 inches
Width = 1 inch
Height = 8.5 inches
Surface Area of Book A = 2(6.5*1) + 2(6.5*8.5) + 2(1*8.5)
Surface Area of Book A = 13 + 110.5 + 17
Surface Area of Book A = 140.5 in^2
For Book B:
Length = 5.5 inches
Width = 2 inches
Height = 8 inches
Surface Area of Book B = 2(5.5*2) + 2(5.5*8) + 2(2*8)
Surface Area of Book B = 22 + 88 + 32
Surface Area of Book B = 142 in^2
Therefore, Book A has a surface area of 140.5 in^2, and Book B has a surface area of 142 in^2. Book A will require less wrapping paper as its surface area is less than that of Book B. The provided responses do not seem accurate based on the calculations above.