To solve the system of equations using substitution, we'll start by solving one equation for one variable and then substituting it into the other equation.
Given:
y = 2 + 3x ...(Equation 1)
4x - 3y = 16 ...(Equation 2)
Let's solve Equation 1 for y:
y = 2 + 3x
Now, we'll substitute this value of y into Equation 2:
4x - 3(2 + 3x) = 16
Simplify:
4x - 6 - 9x = 16
-5x - 6 = 16
-5x = 22
x = -22/5
Now that we have the value of x, we can substitute it back into Equation 1 to find y:
y = 2 + 3(-22/5)
y = 2 - 66/5
y = (10 - 66)/5
y = -56/5
Therefore, the solution is (-22/5, -56/5), which is approximately (-4.4, -11.2).
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Solve the system of two equations using substitution. y = 2 + 3x 4x - 3y 16 (1 point) O (-2, 4) O (-2,-4) O (2,8) (2, 10)
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