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At a summer camp, 20% of the students come from out of state. Megan wants to simulate cabins of 8 campers. She generates random digits from 0 to 9 and lets the digits 0 and 1 represent a camper from out of state. The table below shows her results.

69531217

89542756

89001254

01346895

12468503

20312346

79564328

59868542

75891003

56103249

58630126

57498510

76134860

52974168

03164985

03289642

68533236

94210145

70215789

32605254



What is the experimental probability that in a cabin of 8 campers, none is from out of state?

A. Fraction is 1 over 20
B. one-tenth
C. one-fifth
D. one-fourth
The random digits 0 and 1 represent campers from out of state. Therefore, the digits 2 through 9 represent campers who are not from out of state. For a cabin of 8 campers to have no campers from out of state, all 8 campers must have digits from 2 through 9.

The probability of generating a digit from 2 through 9 is 8 out of 10, or 0.8.

Therefore, the experimental probability of a cabin having no campers from out of state is:

0.8 x 0.8 x 0.8 x 0.8 x 0.8 x 0.8 x 0.8 x 0.8 = 0.16777216

Rounding to the nearest hundredth, that is 0.17.

Therefore, the answer is not listed in the multiple choices given.
At a summer camp, 20% of the students come from out of state. Megan wants to simulate cabins of 8 campers. She generates random digits from 0 to 9 and lets the digits 0 and 1 represent a camper from out of state. The table below shows her results.

69531217

89542756

89001254

01346895

12468503

20312346

79564328

59868542

75891003

56103249

58630126

57498510

76134860

52974168

03164985

03289642

68533236

94210145

70215789

32605254



What is the experimental probability that in a cabin of 8 campers, none is from out of state?

A. Fraction is 1 over 20
B. one-tenth
C. one-fifth
D. one-fourth

which answer is closest
The experimental probability that in a cabin of 8 campers, none is from out of state is approximately 0.17. This answer is not listed in the multiple choices given.
How many ways can six books be arranged on a shelf?
A. 21
B. 120
C. 360
D. 720
If there are six books, then the first book has 6 options of where to be placed, the second book has 5 possible options remaining for where to be placed, the third book has 4 options, and so on, down to the final book, which has only 1 option left.

To find all possible arrangements of the books, you need to multiply the number of options for each book.

Therefore, the total number of ways to arrange six books on a shelf is:

6 x 5 x 4 x 3 x 2 x 1 = 720

Therefore, the answer is D) 720.
There are eight girls competing in an ice-skating competition. In how many ways can they finish in first, second, and third place?
A. 336
B. 1,680
C. 2,016
D. 40,320
The first place can be taken by any of the eight girls. Once the first place is taken, there are seven girls remaining who can take second place. Once second place is taken, there are six remaining girls who can take third place.

Therefore, the total number of ways the girls can finish in first, second, and third place is:

8 x 7 x 6 = 336

Therefore, the answer is A) 336.
How many ways can a president and vice president be selected from a class of 12?

A. 23
B. 72
C. 132
D. 1,320
The president can be selected from any of the 12 students, while the vice president can be selected from any of the remaining 11 students.

Therefore, the total number of ways to select a president and vice president from a class of 12 is:

12 x 11 = 132

Therefore, the answer is C) 132.
How many ways can seven students line up for a class picture?
A. 5,040
B. 210
C. 28
D. 7
To find the number of ways seven students can line up for a class picture, you need to calculate 7! (7 factorial), which is equal to:

7! = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5,040

Therefore, the answer is A) 5,040.