To find the rate of change in the squirrel's height above the ground, we divide the change in height by the time it took for the squirrel to move.
Change in height = 100 feet - 45 feet = 55 feet
Time = 5.25 seconds
Rate of change = Change in height / Time
Rate of change = 55 feet / 5.25 seconds ≈ 10.48 feet/second
Therefore, the quotient that describes the rate of change in the squirrel's height above the ground is 10.48 feet/second.
Bot a squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground. Give your answer to the nearest hundredth. Pick one of these answers. the quotient that describes the rate of change in the squirrel's height above the ground is 19.05 feet/second. the quotient that describes the rate of changes in the squirrel's height above ground is -10.48 feet/second. the quotient that describes the rate of change in the squirrel's height above ground is -19.05 feet/second. the quotient that describes the rate of change in the squirrel's height above ground is 10.48 feet/second.
1 answer
1 answer