Ws = 500kg * 9.8N/kg = 4900 N. = Wt. of safe.
Fv = 4900 N. = Force perpendicular to floor.
Fk = u*Fv = u*4900 = Force of kinetic friction.
Fn = Fap - Fk = m*a
(385+300) - 490u = m*0 = 0
685 - 4900u = 0
-4900u = -685
u = 0.140.
Bonnie and Clyde are sliding 500 bank safe across the floor to their getaway car. The safe slides with a constant speed if Clyde pushes from behind with 385 of force while Bonnie pulls forward on a rope with 300 of force.What is the safe's coefficient of kinetic friction on the bank floor?
2 answers
Excellent if clearly mention the given data and free body daigram give more weightage thank you