To solve this problem, we need to write the balanced chemical equation for the reaction:
NH3 (g) ⇌ NH4+ + NH3 (aq)
Given that 7 mol of NH3 is placed in a 14 L flask, the initial concentration of NH3 can be calculated as follows:
Initial concentration of NH3 = 7 mol / 14 L = 0.5 M
At equilibrium, the concentration of NH4+ is given as 0.2 M.
Using an ICE (Initial-Change-Equilibrium) table:
NH3 ⇌ NH4+
Initial 0.5 M 0 M
Change -x +x
Equilibrium (0.5 - x) M x M
Since NH4+ is a product, x = 0.2 M at equilibrium.
Substitute the equilibrium concentrations into the equilibrium expression for Kc:
Kc = [NH4+][NH3] / [NH3]
Kc = (0.2) / (0.5 - 0.2)
Kc = 0.2 / 0.3
Kc = 0.67
Therefore, the equilibrium constant Kc for this reaction is 0.67.
Bomai places 7mol of Ammonia (NH3) in 14L flask.At Eqiulibrium 0.2M Ammonium (NH4
+
) was found in the flask. What is the equilibrium constant Kc for Bomai places 7mol of Ammonia (NH3) in 14L flask.At Eqiulibrium 0.2M Ammonium (NH4
+
) was found in the flask. What is the equilibrium constant Kc for this reaction?
II) What is the equilibrium constant Kc for this reaction?
II) What is the equilibrium constant Kc for this reaction?
Explain step by step
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