Bobby wants to arrange 24 baseball cards in an array.

Question

Which of the following shows 3
ways the cards could be displayed?
(1 point)
02x12,4x4,6x8
03x 12,4x6,6x6
02x12,3x8,4x6
02x14,3x8,4x6

Answer 1

To arrange 24 baseball cards in an array, Bobby can use different factor pairs of 24. The goal is to express the arrangements in the form of \( a \times b \), where \( a \) and \( b \) are factors of 24.

The factors of 24 are:

• \( 1 \times 24 \)
• \( 2 \times 12 \)
• \( 3 \times 8 \)
• \( 4 \times 6 \)

Based on these combinations, the valid displays would be:

1. \( 2 \times 12 \)
2. \( 3 \times 8 \)
3. \( 4 \times 6 \)

Looking at the provided options:

1. \( 02 \times 12, 4 \times 4, 6 \times 8 \) → \( 4 \times 4 \) is not valid because \( 4 \times 4 = 16 \), not 24.
2. \( 03 \times 12, 4 \times 6, 6 \times 6 \) → \( 6 \times 6 \) is not valid because \( 6 \times 6 = 36 \), not 24.
3. \( 02 \times 12, 3 \times 8, 4 \times 6 \) → All valid configurations that multiply to 24.
4. \( 02 \times 14, 3 \times 8, 4 \times 6 \) → \( 2 \times 14 \) is not valid because \( 2 \times 14 = 28 \), not 24.

Thus, the correct answer is \( 02 \times 12, 3 \times 8, 4 \times 6 \).