To find the amount that Bobby and Emilia will have in their savings account after one year with continuous compounding, we can use the formula:
\[ A = Pe^{rt} \]
Where:
- \(A\) is the amount of money accumulated after time \(t\),
- \(P\) is the principal amount (the initial deposit),
- \(e\) is approximately 2.71828,
- \(r\) is the annual interest rate (as a decimal),
- \(t\) is the time in years.
Given:
- \(P = 600.00\)
- \(r = 0.03\) (3% as a decimal)
- \(t = 1\)
Now we can plug in the values:
\[ A = 600.00 \cdot e^{0.03 \cdot 1} \]
First, calculate \(0.03 \cdot 1\):
\[ 0.03 \cdot 1 = 0.03 \]
Now calculate \(e^{0.03}\):
Using the approximation \(e \approx 2.71828\):
\[ e^{0.03} \approx 2.71828^{0.03} \approx 1.03045453395 \]
Now, multiply the principal by \(e^{0.03}\):
\[ A \approx 600.00 \cdot 1.03045453395 \]
Calculating the multiplication:
\[ A \approx 618.27272037 \]
Now round to the nearest cent:
\[ A \approx 618.27 \]
Thus, Bobby and Emilia will be able to spend approximately $618.27.