To solve this problem, we need to determine the genotype of the other parent based on the children produced.
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The first child has blonde hair (bb). This means that both alleles inherited from the parents must be recessive (b). To have a child with blonde hair, one parent must contribute a recessive allele (b).
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The second child has brown hair (BB). This means that the child received a dominant allele (B) from both parents.
From the information given, we know:
- The brown-haired parent (Bb) can pass on either a B or a b.
- The child with blonde hair must have inherited a b from both parents. Therefore, the other parent must also have contributed a recessive allele (b).
Given that the brown-haired parent (Bb) can give either B or b, the other parent must have at least one recessive allele (b) to produce a blond child. However, since the second child has brown hair, the other parent can either be homozygous dominant (BB) or heterozygous (Bb).
- If the other parent is bb, they can only provide b alleles, which is consistent because they contributed b for the first child.
- If the other parent is BB, they cannot contribute any b alleles, which would not produce the blonde-haired child.
Thus, the only combination that fits all conditions stated is:
Bb, brown hair.
This means the other parent has brown hair but is a carrier of the blonde hair allele (b).