μk = (Ff/Fn) = (Ff/mgsinθ)
Ff = ma = (2kg)(v^2/L)
Fn = mgsinθ = (2kg)(9.8m/s^2)(sin35°)
μk = (v^2/Lgsinθ)
μk = (v^2/(Lgsin35°))
blocks 1 and 2 of masses 2 kg and 4kg, respectively, are connected by a light string, as shown above. These blocks are further connected to a block of mass 3kg by another light string that passes overr a pully of negligible mass and friction. Blocks 1 and 2 move with a constant velocity v down the inclined plane, which makes an angle 35 degrees with the horizontal. the frictional force between each of the blocks and the incline plane is the same. deterin the coefficient of kinetic friction between block 1 and the incline plane.
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