f = m a
m g - t = m a
t = m g - m a = m (g - a)
t = 2.45 (9.80 - 2.55)
answer units are Newtons
Block A (Mass = 3.500 kg) and Block B (Mass = 2.450 kg) are attached by a massless string Block A sits on a horizontal tabletop. There is friction between the surface and Block A. The string passes overa frictionless, massless pulley. Block B hangs down vertically as shown. When the two blocks are released, Block B accelerates downward at a rate of 2.550 m/s2. What is the tension in the string?
1 answer
1 answer