Block 1, of mass m1 = 0.650kg , is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2, as shown. For an angle of θ = 30.0∘ and a coefficient of kinetic friction between block 2 and the plane of μ = 0.400, an acceleration of magnitude a = 0.600m/s2 is observed for block 2.

Question

Part A
Find the mass of block 2, m2.

Answer 1

I had a similar question but i forgot how to do it

Answer 2

they why do you [post if you don't have the answer!^^^

Answer 3

(m1)(g – a) = (m2)(a + gsin(θ) + μgcos(θ))
(0.650)(9.80-0.600)=(m2)(0.600+9.8*sin(30)+0.400*9.80*cos(30))
m2=0.672301423 kg
three sig figs---->m2=0.672 kg

Answer 4

this was kool!

Answer 5

Kinda funny how some of these questions get answered years later