Bismuth – 210 is an alpha emitter. Once Bismuth 210 undergoes alpha decay, what is the resulting atomic number of the decay product?
2 answers
The resulting atomic number of the decay product is 83, which is the atomic number of Polonium-210.
NOPE.
No, Bi is 83. The decay product is atomic mass 81 and mass number 206; i.e., 210 - 4 = 206
83Bi210 ==> 2He4 + 81Tl206
C'mon. Stop this non-sense. This autogeneration with answers is posting too many wrong answers.
No, Bi is 83. The decay product is atomic mass 81 and mass number 206; i.e., 210 - 4 = 206
83Bi210 ==> 2He4 + 81Tl206
C'mon. Stop this non-sense. This autogeneration with answers is posting too many wrong answers.