You should have a 3D diagram.
let the distance on the ground be x
x^2 = 80^2 + 60^2
let the distance from start to finish be y
y^2 = x^2 + 30^2
= 80^2 + 60^2 + 30^2
10900
y = √10900 = 104.4 m
or, using vectors
distance vector
= (0,80,0) + (60,0,0) + (0,0,30)
= )60,80,30)
magnitude = √(80^2 + 60^2 + 30^2)
= as before
Bird flies 80m east, then 60m south, then straight up
In to sky for 30m.
A)at this point how far is bird from his nest?
1 answer