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Bi2(g) + 2KI(ag) -> 2KBr(ag) + I2(s)

• Br2 gains electrons and is oxidized. I- (in KI) loses electrons and is reduced.
• Br2 loses electrons and is oxidized. I- (in KI) gains electrons and is reduced.
• I- (in KI) gains electrons and is oxidized. Br loses electrons and is reduced.
• I- (in KI loses electrons and is oxidized. Br gains electrons and is reduced.

1 answer

The correct statement is:

• Br2 gains electrons and is reduced. I- (in KI) loses electrons and is oxidized.