The distance of Bertha's dive from the starting platform is 45 m, and the distance of Vernon's dive from the starting platform is 9 m.
To find how many times farther Bertha's dive is, we divide the distance of Bertha's dive by the distance of Vernon's dive:
45/9 = <<45/9=5>>5.
Therefore, the end of Bertha's dive is 5 times farther than the end of Vernon's dive.
The answer is 5.
Bertha and Vernon are competing in a diving competition. Bertha's dive ended -45 m from the starting platform. Vernon's dive ended -9 m from the starting platform. How many times farther was the end of Bertha's dive than the end of Vernon's dive? (1 point)
405
-36
36
5
1 answer