Bert is planning to open a savings account that earns 1.6% simple interest yearly. He wants to earn exactly $144 in interest after 3 years. How much money should he deposit?

1 answer

To find out how much money Bert should deposit in order to earn exactly $144 in interest after 3 years with a simple interest rate of 1.6%, we can use the formula for simple interest:

\[ I = P \times r \times t \]

where:

  • \( I \) is the interest earned,
  • \( P \) is the principal amount (the initial deposit),
  • \( r \) is the yearly interest rate (in decimal form),
  • \( t \) is the time in years.

Given:

  • \( I = 144 \) dollars,
  • \( r = 1.6% = 0.016 \),
  • \( t = 3 \) years,

we need to solve for \( P \).

Substituting the values into the formula:

\[ 144 = P \times 0.016 \times 3 \]

Calculating \( 0.016 \times 3 \):

\[ 0.016 \times 3 = 0.048 \]

Now the equation becomes:

\[ 144 = P \times 0.048 \]

To find \( P \), divide both sides by \( 0.048 \):

\[ P = \frac{144}{0.048} \]

Now performing the division:

\[ P = 3000 \]

Therefore, Bert should deposit $3,000 to earn exactly $144 in interest after 3 years at a rate of 1.6%.