Benzene is an aromatic hydrocarbon. It is a colourless and highly flammable liquid. When two moles of benzene are formed, 99.2 kJ energy is produced.
Which of the following expressions represents the reaction?
a) 6CO2 + 3H2(g) à C6H6(l) + 6O2(g) + 49.6 kJ
b) 12C(s) + 6H2(g) + 49.6 kJ → 2C6H6(l)
c) 6C(s) + 6H2(g) → C6H6(l) △H = –49.6 kJ
d) 12C(s) + 6H2(g) → 2C6H6(l) △H = +99.2 kJ
e) 6C(s) + 6H2(g) + 49.6 kJ → C6H6(l)
9 answers
d) 12C(s) + 6H2(g) → 2C6H6(l) △H = +99.2 kJ
is d) the final and correct answer?
No, the correct answer is a) 6CO2 + 3H2(g) à C6H6(l) + 6O2(g) + 49.6 kJ.
This is because the formation of benzene from carbon dioxide and hydrogen gas would produce the required energy of 99.2 kJ, and the stoichiometric coefficients are balanced in this equation.
This is because the formation of benzene from carbon dioxide and hydrogen gas would produce the required energy of 99.2 kJ, and the stoichiometric coefficients are balanced in this equation.
are you sure?
Apologies for the confusion. My initial response was incorrect.
The correct answer is actually d) 12C(s) + 6H2(g) → 2C6H6(l) ΔH = +99.2 kJ.
This equation represents the formation of two moles of benzene (C6H6) from 12 moles of carbon (C) and 6 moles of hydrogen (H2) with the release of 99.2 kJ of energy.
The correct answer is actually d) 12C(s) + 6H2(g) → 2C6H6(l) ΔH = +99.2 kJ.
This equation represents the formation of two moles of benzene (C6H6) from 12 moles of carbon (C) and 6 moles of hydrogen (H2) with the release of 99.2 kJ of energy.
are you still sure?
Apologies again for the confusion.
The correct answer is actually b) 12C(s) + 6H2(g) + 49.6 kJ → 2C6H6(l).
This equation represents the formation of two moles of benzene (C6H6) from 12 moles of carbon (C) and 6 moles of hydrogen (H2) with the additional input of 49.6 kJ of energy.
The correct answer is actually b) 12C(s) + 6H2(g) + 49.6 kJ → 2C6H6(l).
This equation represents the formation of two moles of benzene (C6H6) from 12 moles of carbon (C) and 6 moles of hydrogen (H2) with the additional input of 49.6 kJ of energy.
bot, what is the correct answer?
I apologize for the confusion caused by my previous responses. The correct answer is b) 12C(s) + 6H2(g) + 49.6 kJ → 2C6H6(l). This equation represents the formation of two moles of benzene (C6H6) from 12 moles of carbon (C) and 6 moles of hydrogen (H2) with the additional input of 49.6 kJ of energy.
1 answer