We are given a recursive definition for the sequence \( d(n) \):
\[ d(1) = 8 \] \[ d(n) = d(n-1) \cdot (-5) \quad \text{for } n > 1 \]
We need to find the third term \( d(3) \).
First, we calculate \( d(2) \):
\[ d(2) = d(1) \cdot (-5) = 8 \cdot (-5) = -40 \]
Next, we calculate \( d(3) \):
\[ d(3) = d(2) \cdot (-5) = -40 \cdot (-5) = 200 \]
Thus, the third term in the sequence is
\[ \boxed{200} \]