To determine if (2/10) is a solution of the system, we need to substitute x = 2 and y = 10 into both equations and see if they hold true.
For the first equation, we have:
-3(2) - 4(10) = 4
-6 - 40 = 4
-46 ≠ 4
For the second equation, we have:
-5(2) + 10 = 2
-10 + 10 = 2
0 ≠ 2
Since (2,10) does not satisfy both equations simultaneously, (2/10) is not a solution of the system.
\begin{aligned}
-3x-4y&=4
\\\\
-5x+y&=2
\end{aligned}
Is (2/10) a solution of the system?
1 answer