To find the amount of water left in the cooler, we need to subtract the amount of water that leaked out (2 5/6 gallons) from the amount of water originally filled (6 1/2 gallons).
First, let's convert 6 1/2 gallons to an improper fraction.
6 1/2 = (2*6 + 1)/2 = 13/2
Next, let's convert 2 5/6 gallons to an improper fraction.
2 5/6 = (6*2 + 5)/6 = 17/6
Now, we can subtract the fraction of water leaked from the fraction of water filled.
(13/2) - (17/6)
To subtract fractions, we need to have the same denominator. The least common multiple of 2 and 6 is 6, so we need to rewrite the fractions with a denominator of 6.
(13/2) = (13/2) * (3/3) = 39/6
(17/6) = (17/6) * (1/1) = 17/6
Now, we can subtract the two fractions.
39/6 - 17/6 = 22/6
So, there were 22/6 gallons of water left in the cooler after closing the plug.
To simplify the fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 2.
22/6 = (22/2)/(6/2) = 11/3
Therefore, there were 11/3 gallons of water left in the cooler after closing the plug.
Before your soccer game, you filled a water cooler with 6 1/2
gallons of water.
You forgot to close the plug before you began filling the cooler with water and 2 5/6
gallons leaked out.
How much water was in the cooler after you closed the plug?
(4 points)
1 answer