Before a collision, a 28 kg object is moving at +13 m/s. Find the impulse
2 answers
Hmmmmm. Impulse is equal to change in momentum. There is no change mentioned here
I think the answer is this:
The change of momentum of a system is equal to the net impulse applied to it. Therefore,
delta p=Fnet*deltat=Impulse
In our case, p initial=mv=28kg*13m/s=364 kg*m/s
p final=0 ( the object stops, v=o, p final 0)
delta p = p final- p initial = 0- 364 = -364 kg*m/s
Hope, that's the right answer.
The change of momentum of a system is equal to the net impulse applied to it. Therefore,
delta p=Fnet*deltat=Impulse
In our case, p initial=mv=28kg*13m/s=364 kg*m/s
p final=0 ( the object stops, v=o, p final 0)
delta p = p final- p initial = 0- 364 = -364 kg*m/s
Hope, that's the right answer.
1 answer