Be sure and answer both of the questions listed below: Makayla pushes a 200 kg box of books across the floor. The box accelerates at 0.4 m/s2

Question

. Ignoring outside forces, calculate the force on the box. (1 point)
Responses

80 Newtons
80 Newtons

.8 m/s2
.8 the fraction with numerator m and denominator s squared

500 N
500 N

0.002 m/s2

Answer 1

To calculate the force on the box, we can use Newton's second law of motion, which states that:

\[ F = m \cdot a \]

Where:

• \( F \) is the force (in Newtons),
• \( m \) is the mass (in kilograms),
• \( a \) is the acceleration (in meters per second squared).

Given:

• Mass (\( m \)) = 200 kg
• Acceleration (\( a \)) = 0.4 m/s²

Now, plug in the values:

\[ F = 200 , \text{kg} \cdot 0.4 , \text{m/s}² \]

\[ F = 80 , \text{N} \]

So, the correct force on the box is 80 Newtons.