since BD bisects ABC, DBC = ABD = 3x+15
so now you know that
3x+15 + 3x+15 = 12x
Solve for x as usual, then finish it off.
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BD bisects <ABC, m <ABC=12x and m<ABD=3x+15 find m<DBC
1 answer
BD bisects <ABC, m <ABC=12x and m<ABD=3x+15 find m<DBC
1 answer