In the electrolysis of aluminum oxide (Al₂O₃), the aluminum ions (Al³⁺) and oxide ions (O²⁻) are reduced and oxidized, respectively, at the cathode and anode.
Here are the half-equations for both electrodes:
Cathode Half Equation (Reduction)
At the cathode, aluminum ions gain electrons to form aluminum metal: \[ \text{Al}^{3+} + 3e^- \rightarrow \text{Al (s)} \]
Anode Half Equation (Oxidation)
At the anode, oxide ions lose electrons to form oxygen gas: \[ \text{O}^{2-} \rightarrow \frac{1}{2} \text{O}_2 (g) + 2e^- \]
Overall, during the electrolysis of Al₂O₃, aluminum is produced at the cathode, and oxygen gas is produced at the anode.