Bats are extremely adept at catching insects in midair. If a 62-g bat flying in one direction at 9 m/s catches a 6-g insect flying in the opposite direction at 4 m/s, what is the speed of the bat immediately after catching the insect?

Answer 1

Momentum = m1*V1-m2*V2 = 0.062*9-0.006*4 = 0.558 - 0.024 = 0.534

m1*V = 0.534
0.062*V = 0.534
V = 8.61 m/s.