Batman (mass = 95 kg) jumps straight down from a bridge into a boat (mass = 560 kg) in which a criminal is fleeing. The velocity of the boat is initially +10 m/s. What is the velocity of the boat after Batman lands in it?

Answer 1

Assuming the criminal's weight is included in that of the boat (560 kg), calculate the initial kinetic energy using
KE0 = (1/2)Mv0²
Calculate the new kinetic energy
KE1 = (1/2)(M+m)v²
Equate KE0 and KE1 and solve for v.

Answer 2

Or save yourself the trouble and use the following formula.

I just did this problem.

(m1*v01)/(m1+m2)

Answer 3

don't try this ^^ there wrong

Answer 4

mindy's is right