Bathsheba has 5 paintings in her house, 1 each in a color palette of red, yellow, blue, green, and purple. She hangs them randomly in a horizontal order. What is the probability of hanging the blue painting first, and then the green?(1 point)

Responses

15⋅15
Start Fraction 1 over 5 End Fraction times Start Fraction 1 over 5 End Fraction

15⋅14
Start Fraction 1 over 5 End Fraction times Start Fraction 1 over 4 End Fraction

15
Start Fraction 1 over 5 End Fraction

15+15
Start Fraction 1 over 5 End Fraction plus Start Fraction 1 over 5 End Fraction

1 answer

To find the probability of hanging the blue painting first and then the green painting, we can follow these steps:

  1. Total paintings: There are 5 paintings: red, yellow, blue, green, and purple.
  2. Probability of hanging blue first: Since there are 5 paintings, the probability of choosing the blue painting first is \(\frac{1}{5}\).
  3. Probability of hanging green second: After hanging the blue painting, 4 paintings remain (red, yellow, green, purple). The probability of then choosing the green painting is \(\frac{1}{4}\).

Now, we multiply these two probabilities together to get the total probability of these two events happening in that order:

\[ P(\text{blue first and green second}) = P(\text{blue first}) \times P(\text{green second}) = \frac{1}{5} \times \frac{1}{4} = \frac{1}{20} \]

None of the provided response options explicitly state \(\frac{1}{20}\), but the calculation itself has been followed correctly.

Among the listed responses:

  • Start Fraction 1 over 5 End Fraction times Start Fraction 1 over 4 End Fraction (choice 2) is the correct representation of the probability calculation.

Thus, the final answer is:

\(\text{Start Fraction 1 over 5 End Fraction times Start Fraction 1 over 4 End Fraction}\).