Based on this nuclear reaction equation: 27 13 Al + 1 0 n = 4 2 He + 24 11 Na, calculate the Mass defect for the overall reaction given that the mass defect for He is 0.029396746, the mass defect for Al is 0.2344815, the mass defect for Na is 1.20179

Answer 1

To calculate the mass defect for the overall reaction, we need to determine the total mass defect for each element involved in the reaction.

For Al:
Mass defect = (27 * 1.008664915) + (13 * 0.000548597) - 0.2344815
Mass defect = 27.214683205 + 0.007130771 - 0.2344815
Mass defect = 27.987332476 u

For He:
Mass defect = (4 * 1.00727647) - 0.029396746
Mass defect = 4.02910588 - 0.029396746
Mass defect = 4.000709134 u

For Na:
Mass defect = (24 * 1.008664915) + (11 * 0.000548597) - 1.20179
Mass defect = 24.20795876 + 0.006034567 - 1.20179
Mass defect = 23.012202327 u

Total mass defect for the overall reaction = (27.987332476 + 4.000709134) - (4.02910588 + 23.012202327)
Total mass defect for the overall reaction = 31.98804161 - 27.041308207
Total mass defect for the overall reaction = 4.946733403 u

Therefore, the mass defect for the overall reaction is 4.946733403 atomic mass units.