To calculate the heat released per gram of Al reacted with Fe2O3, we first need to calculate the molar mass of Al.
The molar mass of Al is 26.98 g/mol.
Next, we need to calculate the moles of Al reacting with Fe2O3. From the balanced chemical equation, we see that 2 moles of Al react with 1 mole of Fe2O3.
Since the molar mass of Fe2O3 is 159.69 g/mol, we can calculate the moles of Al reacting with Fe2O3:
1 mol Al = 26.98 g Al
x mol Al = 159.69 g Fe2O3
x = (159.69 g Fe2O3) / (159.69 g/mol Al) = 5.92 mol Al
The heat released per mole of Al reacted is given by the reaction:
2Al(s) + Fe2O3(s) = Al2O3(s) + 2Fe(l)
ΔH = Σ(nΔHf(products)) - Σ(mΔHf(reactants))
ΔH = [2(0) + 2(12.40 kJ)] - [0 + 0] = 24.80 kJ
Therefore, the heat released per mole of Al is 24.80 kJ.
Now, to calculate the heat released per gram of Al:
24.80 kJ / 26.98 g/mol = 0.919 kJ/g
Therefore, the heat released per gram of Al reacted with Fe2O3 is 0.919 kJ/g.
Based on the reaction below
2Al(s) + Fe2O3(s)= Al2O3(s) + 2Fe(l)
Calculate the heat releases in kilojoules per gram of Al reacted with Fe2O3.the standard enthalpy of formation for Fe(l) is 12.40kJ/mol.
1 answer