To prove that triangles \( \triangle ABD \) and \( \triangle DBC \) are congruent by the ASA (Angle-Side-Angle) Congruence Theorem, you must establish two angles and the included side being congruent in each triangle.
Assuming that \( \angle A \) and \( \angle D \) are the angles at vertices A and D, respectively, and that \( AB \) and \( BD \) are the sides connecting those angles, we can summarize the required information:
- You need to show that \( \angle A \cong \angle D \) (as one of the angles) and
- You need to show that the side connecting those angles, \( \overline{AB} \) or \( \overline{BD} \), is congruent.
Therefore, based on the responses provided, the additional information required would be:
- \( \angle A \cong \angle D \) (you need to establish the congruence of these angles).
So the correct option is:
\( \angle A \cong \angle D \).