To balance the chemical equation:
\( \text{Li}_2\text{O} + \text{H}_2\text{O} \rightarrow \text{LiOH} \)
you need to ensure that the number of atoms of each element is the same on both sides of the equation. Here’s how you balance it:
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Lithium (Li): There are 2 lithium atoms in \(\text{Li}_2\text{O}\) and 1 lithium atom in \(\text{LiOH}\). Therefore, you will need 2 \(\text{LiOH}\) on the product side.
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Oxygen (O): In this case, \(\text{Li}_2\text{O}\) provides 1 oxygen atom and \(\text{H}_2\text{O}\) provides another oxygen atom. Thus, there are 2 oxygen atoms in total on the left side, and 2 in \(\text{2LiOH}\).
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Hydrogen (H): From \(\text{H}_2\text{O}\), we have 2 hydrogen atoms, which balance with the 2 hydrogen atoms provided by the 2 \(\text{LiOH}\).
Thus, you can adjust the coefficients to achieve balance:
- 1 for \(\text{Li}_2\text{O}\)
- 1 for \(\text{H}_2\text{O}\)
- 2 for \(\text{LiOH}\)
So the balanced equation is:
\[ 1 \text{Li}_2\text{O} + 1 \text{H}_2\text{O} \rightarrow 2 \text{LiOH} \]
The coefficients are: 1, 1, 2.